Crash Victims Info

Car of mass 1557 crashes and bounces off a wall, the x components are respectively 23 m/s and 2.9 m/s?

If the collision lasts for 0.14 secs what is the magnitude of the impulse due to the collision in units of kg-m/s? What is the magintude of the average force exerted on the automobile during the collision in units of Newtons?

Public Comments

1. Impulse equals change in momentum. The initial velocity is 23 m/s and the final velocity is -2.9 m/s. So ΔP = 1557 kg * (23 m/s + 2.9 m/s) ΔP = 40000 m kg / s = impulse For a constant force (or a force averaged over the time of the collision), the impulse is also equal to the time of the collision times the force. So ΔP = F*Δt F = ΔP/Δt F = (40000 m kg / s) / 0.14 s F = 286000 N