Crash Victims Info

Physics help!?

In a particular crash test, an automobile of mass 1215 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 13 m/s and 3.2 m/s, respectively. If the collision lasts for 0.12 s, and the magnitude of the impulse due to the collision. Answer in units of kg x m/s. Calculate the magnitude of the average force exerted on the automobile during the colli- sion. Answer in units of N.

Public Comments

1. for this, you want to make use of impulse: FΔt =Δ(mv) F=Force Δt = time of collision (.12s) Δ(mv)=change in momentum here, remember that momentum is a vector, so the momentum of rebound has a different sign from the initial momentum, then: F=Δ(mv)/Δt = [1215kg(13-(-3.2))m/s]/0.12s=164,025N