Crash Victims Info

Physics Help Please!?

In a particular crash test, an automobile of mass 1697 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 22 m/s and 2.7 m/s respectively. a) If the collision lasts for 0.17 s, find the magnitude of the impulse due to the collision. Answer in units of kg x m/s b) Calculate the magnitude of the average force exerted on the automobile during the collision Answer in units of N.

Public Comments

1. Impulse= Change of momentum dp dp= p1-p2= dp=[V1- V2]m= dp=[22 - (-2.7)]1697= 24.7 x 1697 dp dp=42,000 kg m/s Average exerted force F= I/dt= dp/dt= 42,000/0.17=250,000 N